C anagram programming code
#include <stdio.h> int check_anagram(char [], char []); int main() { char a[100], b[100]; int flag; printf("Enter first string\n"); gets(a); printf("Enter second string\n"); gets(b); flag = check_anagram(a, b); if (flag == 1) printf("\"%s\" and \"%s\" are anagrams.\n", a, b); else printf("\"%s\" and \"%s\" are not anagrams.\n", a, b); return 0; } int check_anagram(char a[], char b[]) { int first[26] = {0}, second[26] = {0}, c = 0; while (a[c] != '\0') { first[a[c]-'a']++; c++; } c = 0; while (b[c] != '\0') { second[b[c]-'a']++; c++; } for (c = 0; c < 26; c++) { if (first[c] != second[c]) return 0; } return 1; }
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Output of program:
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